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sana akitoThx for your help even if only part a will be answered it would help me a lot :) Ammonia burns in oxygen as shown
4NH3(g) +3O2(g)-->2N2(g)+6H20(l)
In an experiment 15 dm3 of ammonia are used and all the gas volumes are measured at room temperature and pressure
a) What volume of oxygen in dm3 is required for complete combustion?
b) What volume of nitrogen in dm3 will be produced?23 April 2012Comment
andy chuks The equation above shows the mole ratios of the reaction. 4 moles of ammonia (NH3) reacting with 3 moles of Oxygen (O2) produced 2 moles of Nitrogen (N2) and 6 moles of water (H2O).
Note 1 mole of gas is = 22.4dm3
Therefore 4 moles of NH3 = 89.6 dm3
1)
Since it was complete combustion, that means if 15dm3 of NH3 was burnt completely 0.67 moles of... Read All 1024 April 2012
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