periods of pendulums with different lengths.
(a) Solve the formula for g.
(b) Use the table to determine the value of g. (Note: The
units for g are feet per second per second.)
(c) Interpret your result.
T 5 2pB
L
g
,
L (feet) 0.5 1.0 1.5
T (seconds) 0.78 1.11 1.36 28 May 2011Comment
logan edwardsSimple Pendulum Gravity is responsible for an object
falling toward Earth. The farther the object falls, the faster
it is moving when it hits the ground. For each second that
an object falls, its speed increases by a constant amount,
called the acceleration due to gravity, denoted g. One way
to calculate the value of g is to use a simple pendulum. 1028 May 2011
logan edwardsThank you can you help me with this?
The time T for a pendulum to swing back and forth
once is called its period and is given by
where L equals the length of the pendulum. The table lists
the periods of pendulums with different lengths.
(a) Solve the formula for g.
(b) Use the table to determine the value of g. (Note: The
units for g are feet per second per second.)
(c) Interpret your result.
T 5 2pB
L
g
,
L (feet) 0.5 1.0 1.5
T (seconds) 0.78 1.11 1.36 0028 May 2011
logan edwardsI am still needing help 0029 May 2011
logan edwardsAnybody please, I still dont get this.. Thanks 0028 May 2011
andy chuksHi Logan I will give you a guide on how you can solve this problem first know that
period T = 2pi x (L/g)^-2
(L is the length of pendulum, pi is 3.142, and g is the acceleration of gravity)
From the above equation making g
T^2 = (4pi^2 x L)/g
T^2 /L = 4pi^2/g
From the above you have values for L and T,
create a table of values L, T, T^2
using the values of T^2 and L plot a graph of T^2 verses L and find the slope of the graph.
The slope of the graph is equal to [4(pi)^2]/g
Therefore making g subject formula your g is = [4(pi)^2]/Slope 1030 May 2011
logan edwardsthank you this will help me 0030 May 2011
ddynamicboy ddynamichow can i solve a geometry construction?please i need someone to help out. 0013 June 2011
(a) Solve the formula for g.
(b) Use the table to determine the value of g. (Note: The
units for g are feet per second per second.)
(c) Interpret your result.
T 5 2pB
L
g
,
L (feet) 0.5 1.0 1.5
T (seconds) 0.78 1.11 1.36 28 May 2011Comment
falling toward Earth. The farther the object falls, the faster
it is moving when it hits the ground. For each second that
an object falls, its speed increases by a constant amount,
called the acceleration due to gravity, denoted g. One way
to calculate the value of g is to use a simple pendulum.
The time T for a pendulum to swing back and forth
once is called its period and is given by
where L equals the length of the pendulum. The table lists
the periods of pendulums with different lengths.
(a) Solve the formula for g.
(b) Use the table to determine the value of g. (Note: The
units for g are feet per second per second.)
(c) Interpret your result.
T 5 2pB
L
g
,
L (feet) 0.5 1.0 1.5
T (seconds) 0.78 1.11 1.36
period T = 2pi x (L/g)^-2
(L is the length of pendulum, pi is 3.142, and g is the acceleration of gravity)
From the above equation making g
T^2 = (4pi^2 x L)/g
T^2 /L = 4pi^2/g
From the above you have values for L and T,
create a table of values L, T, T^2
using the values of T^2 and L plot a graph of T^2 verses L and find the slope of the graph.
The slope of the graph is equal to [4(pi)^2]/g
Therefore making g subject formula your g is = [4(pi)^2]/Slope